Integrand size = 28, antiderivative size = 224 \[ \int \sec ^6(c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\frac {a^5 \text {arctanh}(\sin (c+d x))}{d}-\frac {5 a^3 b^2 \text {arctanh}(\sin (c+d x))}{d}+\frac {15 a b^4 \text {arctanh}(\sin (c+d x))}{8 d}+\frac {5 a^4 b \sec (c+d x)}{d}-\frac {10 a^2 b^3 \sec (c+d x)}{d}+\frac {b^5 \sec (c+d x)}{d}+\frac {10 a^2 b^3 \sec ^3(c+d x)}{3 d}-\frac {2 b^5 \sec ^3(c+d x)}{3 d}+\frac {b^5 \sec ^5(c+d x)}{5 d}+\frac {5 a^3 b^2 \sec (c+d x) \tan (c+d x)}{d}-\frac {15 a b^4 \sec (c+d x) \tan (c+d x)}{8 d}+\frac {5 a b^4 \sec (c+d x) \tan ^3(c+d x)}{4 d} \]
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Time = 0.28 (sec) , antiderivative size = 224, normalized size of antiderivative = 1.00, number of steps used = 15, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {3169, 3855, 2686, 8, 2691, 200} \[ \int \sec ^6(c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\frac {a^5 \text {arctanh}(\sin (c+d x))}{d}+\frac {5 a^4 b \sec (c+d x)}{d}-\frac {5 a^3 b^2 \text {arctanh}(\sin (c+d x))}{d}+\frac {5 a^3 b^2 \tan (c+d x) \sec (c+d x)}{d}+\frac {10 a^2 b^3 \sec ^3(c+d x)}{3 d}-\frac {10 a^2 b^3 \sec (c+d x)}{d}+\frac {15 a b^4 \text {arctanh}(\sin (c+d x))}{8 d}+\frac {5 a b^4 \tan ^3(c+d x) \sec (c+d x)}{4 d}-\frac {15 a b^4 \tan (c+d x) \sec (c+d x)}{8 d}+\frac {b^5 \sec ^5(c+d x)}{5 d}-\frac {2 b^5 \sec ^3(c+d x)}{3 d}+\frac {b^5 \sec (c+d x)}{d} \]
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Rule 8
Rule 200
Rule 2686
Rule 2691
Rule 3169
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \int \left (a^5 \sec (c+d x)+5 a^4 b \sec (c+d x) \tan (c+d x)+10 a^3 b^2 \sec (c+d x) \tan ^2(c+d x)+10 a^2 b^3 \sec (c+d x) \tan ^3(c+d x)+5 a b^4 \sec (c+d x) \tan ^4(c+d x)+b^5 \sec (c+d x) \tan ^5(c+d x)\right ) \, dx \\ & = a^5 \int \sec (c+d x) \, dx+\left (5 a^4 b\right ) \int \sec (c+d x) \tan (c+d x) \, dx+\left (10 a^3 b^2\right ) \int \sec (c+d x) \tan ^2(c+d x) \, dx+\left (10 a^2 b^3\right ) \int \sec (c+d x) \tan ^3(c+d x) \, dx+\left (5 a b^4\right ) \int \sec (c+d x) \tan ^4(c+d x) \, dx+b^5 \int \sec (c+d x) \tan ^5(c+d x) \, dx \\ & = \frac {a^5 \text {arctanh}(\sin (c+d x))}{d}+\frac {5 a^3 b^2 \sec (c+d x) \tan (c+d x)}{d}+\frac {5 a b^4 \sec (c+d x) \tan ^3(c+d x)}{4 d}-\left (5 a^3 b^2\right ) \int \sec (c+d x) \, dx-\frac {1}{4} \left (15 a b^4\right ) \int \sec (c+d x) \tan ^2(c+d x) \, dx+\frac {\left (5 a^4 b\right ) \text {Subst}(\int 1 \, dx,x,\sec (c+d x))}{d}+\frac {\left (10 a^2 b^3\right ) \text {Subst}\left (\int \left (-1+x^2\right ) \, dx,x,\sec (c+d x)\right )}{d}+\frac {b^5 \text {Subst}\left (\int \left (-1+x^2\right )^2 \, dx,x,\sec (c+d x)\right )}{d} \\ & = \frac {a^5 \text {arctanh}(\sin (c+d x))}{d}-\frac {5 a^3 b^2 \text {arctanh}(\sin (c+d x))}{d}+\frac {5 a^4 b \sec (c+d x)}{d}-\frac {10 a^2 b^3 \sec (c+d x)}{d}+\frac {10 a^2 b^3 \sec ^3(c+d x)}{3 d}+\frac {5 a^3 b^2 \sec (c+d x) \tan (c+d x)}{d}-\frac {15 a b^4 \sec (c+d x) \tan (c+d x)}{8 d}+\frac {5 a b^4 \sec (c+d x) \tan ^3(c+d x)}{4 d}+\frac {1}{8} \left (15 a b^4\right ) \int \sec (c+d x) \, dx+\frac {b^5 \text {Subst}\left (\int \left (1-2 x^2+x^4\right ) \, dx,x,\sec (c+d x)\right )}{d} \\ & = \frac {a^5 \text {arctanh}(\sin (c+d x))}{d}-\frac {5 a^3 b^2 \text {arctanh}(\sin (c+d x))}{d}+\frac {15 a b^4 \text {arctanh}(\sin (c+d x))}{8 d}+\frac {5 a^4 b \sec (c+d x)}{d}-\frac {10 a^2 b^3 \sec (c+d x)}{d}+\frac {b^5 \sec (c+d x)}{d}+\frac {10 a^2 b^3 \sec ^3(c+d x)}{3 d}-\frac {2 b^5 \sec ^3(c+d x)}{3 d}+\frac {b^5 \sec ^5(c+d x)}{5 d}+\frac {5 a^3 b^2 \sec (c+d x) \tan (c+d x)}{d}-\frac {15 a b^4 \sec (c+d x) \tan (c+d x)}{8 d}+\frac {5 a b^4 \sec (c+d x) \tan ^3(c+d x)}{4 d} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(1219\) vs. \(2(224)=448\).
Time = 8.12 (sec) , antiderivative size = 1219, normalized size of antiderivative = 5.44 \[ \int \sec ^6(c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\frac {b \left (600 a^4-1000 a^2 b^2+89 b^4\right ) \cos ^5(c+d x) (a+b \tan (c+d x))^5}{120 d (a \cos (c+d x)+b \sin (c+d x))^5}+\frac {\left (-8 a^5+40 a^3 b^2-15 a b^4\right ) \cos ^5(c+d x) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right ) (a+b \tan (c+d x))^5}{8 d (a \cos (c+d x)+b \sin (c+d x))^5}+\frac {\left (8 a^5-40 a^3 b^2+15 a b^4\right ) \cos ^5(c+d x) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right ) (a+b \tan (c+d x))^5}{8 d (a \cos (c+d x)+b \sin (c+d x))^5}+\frac {\left (25 a b^4+2 b^5\right ) \cos ^5(c+d x) (a+b \tan (c+d x))^5}{80 d \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )^4 (a \cos (c+d x)+b \sin (c+d x))^5}+\frac {\left (600 a^3 b^2+200 a^2 b^3-375 a b^4-31 b^5\right ) \cos ^5(c+d x) (a+b \tan (c+d x))^5}{240 d \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )^2 (a \cos (c+d x)+b \sin (c+d x))^5}+\frac {b^5 \cos ^5(c+d x) \sin \left (\frac {1}{2} (c+d x)\right ) (a+b \tan (c+d x))^5}{20 d \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )^5 (a \cos (c+d x)+b \sin (c+d x))^5}-\frac {b^5 \cos ^5(c+d x) \sin \left (\frac {1}{2} (c+d x)\right ) (a+b \tan (c+d x))^5}{20 d \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^5 (a \cos (c+d x)+b \sin (c+d x))^5}+\frac {\left (-25 a b^4+2 b^5\right ) \cos ^5(c+d x) (a+b \tan (c+d x))^5}{80 d \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^4 (a \cos (c+d x)+b \sin (c+d x))^5}+\frac {\left (-600 a^3 b^2+200 a^2 b^3+375 a b^4-31 b^5\right ) \cos ^5(c+d x) (a+b \tan (c+d x))^5}{240 d \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^2 (a \cos (c+d x)+b \sin (c+d x))^5}+\frac {\cos ^5(c+d x) \left (-600 a^4 b \sin \left (\frac {1}{2} (c+d x)\right )+1000 a^2 b^3 \sin \left (\frac {1}{2} (c+d x)\right )-89 b^5 \sin \left (\frac {1}{2} (c+d x)\right )\right ) (a+b \tan (c+d x))^5}{120 d \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right ) (a \cos (c+d x)+b \sin (c+d x))^5}+\frac {\cos ^5(c+d x) \left (200 a^2 b^3 \sin \left (\frac {1}{2} (c+d x)\right )-31 b^5 \sin \left (\frac {1}{2} (c+d x)\right )\right ) (a+b \tan (c+d x))^5}{120 d \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )^3 (a \cos (c+d x)+b \sin (c+d x))^5}+\frac {\cos ^5(c+d x) \left (-200 a^2 b^3 \sin \left (\frac {1}{2} (c+d x)\right )+31 b^5 \sin \left (\frac {1}{2} (c+d x)\right )\right ) (a+b \tan (c+d x))^5}{120 d \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^3 (a \cos (c+d x)+b \sin (c+d x))^5}+\frac {\cos ^5(c+d x) \left (600 a^4 b \sin \left (\frac {1}{2} (c+d x)\right )-1000 a^2 b^3 \sin \left (\frac {1}{2} (c+d x)\right )+89 b^5 \sin \left (\frac {1}{2} (c+d x)\right )\right ) (a+b \tan (c+d x))^5}{120 d \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right ) (a \cos (c+d x)+b \sin (c+d x))^5} \]
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Time = 1.98 (sec) , antiderivative size = 236, normalized size of antiderivative = 1.05
method | result | size |
parts | \(\frac {a^{5} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}+\frac {b^{5} \left (\frac {\sec \left (d x +c \right )^{5}}{5}-\frac {2 \sec \left (d x +c \right )^{3}}{3}+\sec \left (d x +c \right )\right )}{d}+\frac {10 a^{3} b^{2} \left (\frac {\sin \left (d x +c \right )^{3}}{2 \cos \left (d x +c \right )^{2}}+\frac {\sin \left (d x +c \right )}{2}-\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}+\frac {5 a \,b^{4} \left (\frac {\sin \left (d x +c \right )^{5}}{4 \cos \left (d x +c \right )^{4}}-\frac {\sin \left (d x +c \right )^{5}}{8 \cos \left (d x +c \right )^{2}}-\frac {\sin \left (d x +c \right )^{3}}{8}-\frac {3 \sin \left (d x +c \right )}{8}+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )}{d}+\frac {10 a^{2} b^{3} \left (\frac {\sec \left (d x +c \right )^{3}}{3}-\sec \left (d x +c \right )\right )}{d}+\frac {5 a^{4} b \sec \left (d x +c \right )}{d}\) | \(236\) |
derivativedivides | \(\frac {a^{5} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+\frac {5 a^{4} b}{\cos \left (d x +c \right )}+10 a^{3} b^{2} \left (\frac {\sin \left (d x +c \right )^{3}}{2 \cos \left (d x +c \right )^{2}}+\frac {\sin \left (d x +c \right )}{2}-\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+10 a^{2} b^{3} \left (\frac {\sin \left (d x +c \right )^{4}}{3 \cos \left (d x +c \right )^{3}}-\frac {\sin \left (d x +c \right )^{4}}{3 \cos \left (d x +c \right )}-\frac {\left (2+\sin \left (d x +c \right )^{2}\right ) \cos \left (d x +c \right )}{3}\right )+5 a \,b^{4} \left (\frac {\sin \left (d x +c \right )^{5}}{4 \cos \left (d x +c \right )^{4}}-\frac {\sin \left (d x +c \right )^{5}}{8 \cos \left (d x +c \right )^{2}}-\frac {\sin \left (d x +c \right )^{3}}{8}-\frac {3 \sin \left (d x +c \right )}{8}+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )+b^{5} \left (\frac {\sin \left (d x +c \right )^{6}}{5 \cos \left (d x +c \right )^{5}}-\frac {\sin \left (d x +c \right )^{6}}{15 \cos \left (d x +c \right )^{3}}+\frac {\sin \left (d x +c \right )^{6}}{5 \cos \left (d x +c \right )}+\frac {\left (\frac {8}{3}+\sin \left (d x +c \right )^{4}+\frac {4 \sin \left (d x +c \right )^{2}}{3}\right ) \cos \left (d x +c \right )}{5}\right )}{d}\) | \(316\) |
default | \(\frac {a^{5} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+\frac {5 a^{4} b}{\cos \left (d x +c \right )}+10 a^{3} b^{2} \left (\frac {\sin \left (d x +c \right )^{3}}{2 \cos \left (d x +c \right )^{2}}+\frac {\sin \left (d x +c \right )}{2}-\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+10 a^{2} b^{3} \left (\frac {\sin \left (d x +c \right )^{4}}{3 \cos \left (d x +c \right )^{3}}-\frac {\sin \left (d x +c \right )^{4}}{3 \cos \left (d x +c \right )}-\frac {\left (2+\sin \left (d x +c \right )^{2}\right ) \cos \left (d x +c \right )}{3}\right )+5 a \,b^{4} \left (\frac {\sin \left (d x +c \right )^{5}}{4 \cos \left (d x +c \right )^{4}}-\frac {\sin \left (d x +c \right )^{5}}{8 \cos \left (d x +c \right )^{2}}-\frac {\sin \left (d x +c \right )^{3}}{8}-\frac {3 \sin \left (d x +c \right )}{8}+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )+b^{5} \left (\frac {\sin \left (d x +c \right )^{6}}{5 \cos \left (d x +c \right )^{5}}-\frac {\sin \left (d x +c \right )^{6}}{15 \cos \left (d x +c \right )^{3}}+\frac {\sin \left (d x +c \right )^{6}}{5 \cos \left (d x +c \right )}+\frac {\left (\frac {8}{3}+\sin \left (d x +c \right )^{4}+\frac {4 \sin \left (d x +c \right )^{2}}{3}\right ) \cos \left (d x +c \right )}{5}\right )}{d}\) | \(316\) |
parallelrisch | \(\frac {-a \left (\cos \left (5 d x +5 c \right )+5 \cos \left (3 d x +3 c \right )+10 \cos \left (d x +c \right )\right ) \left (a^{4}-5 a^{2} b^{2}+\frac {15}{8} b^{4}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+a \left (\cos \left (5 d x +5 c \right )+5 \cos \left (3 d x +3 c \right )+10 \cos \left (d x +c \right )\right ) \left (a^{4}-5 a^{2} b^{2}+\frac {15}{8} b^{4}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+5 b \left (\left (5 a^{4}-\frac {20}{3} a^{2} b^{2}+\frac {8}{15} b^{4}\right ) \cos \left (3 d x +3 c \right )+\left (a^{4}-\frac {4}{3} a^{2} b^{2}+\frac {8}{75} b^{4}\right ) \cos \left (5 d x +5 c \right )+8 \left (a^{4}-\frac {4}{3} a^{2} b^{2}+\frac {1}{15} b^{4}\right ) \cos \left (2 d x +2 c \right )+2 \left (a^{4}-2 a^{2} b^{2}+\frac {1}{5} b^{4}\right ) \cos \left (4 d x +4 c \right )+\left (4 a^{3} b -\frac {1}{2} a \,b^{3}\right ) \sin \left (2 d x +2 c \right )+\left (2 a^{3} b -\frac {5}{4} a \,b^{3}\right ) \sin \left (4 d x +4 c \right )+2 \left (5 a^{4}-\frac {20}{3} a^{2} b^{2}+\frac {8}{15} b^{4}\right ) \cos \left (d x +c \right )+6 a^{4}-\frac {20 a^{2} b^{2}}{3}+\frac {58 b^{4}}{75}\right )}{d \left (\cos \left (5 d x +5 c \right )+5 \cos \left (3 d x +3 c \right )+10 \cos \left (d x +c \right )\right )}\) | \(365\) |
risch | \(\frac {b \,{\mathrm e}^{i \left (d x +c \right )} \left (1200 i a^{3} b \,{\mathrm e}^{2 i \left (d x +c \right )}+600 i a^{3} b +600 a^{4} {\mathrm e}^{8 i \left (d x +c \right )}-1200 a^{2} b^{2} {\mathrm e}^{8 i \left (d x +c \right )}+120 b^{4} {\mathrm e}^{8 i \left (d x +c \right )}-1200 i a^{3} b \,{\mathrm e}^{6 i \left (d x +c \right )}-150 i a \,b^{3} {\mathrm e}^{2 i \left (d x +c \right )}+2400 a^{4} {\mathrm e}^{6 i \left (d x +c \right )}-3200 a^{2} b^{2} {\mathrm e}^{6 i \left (d x +c \right )}+160 b^{4} {\mathrm e}^{6 i \left (d x +c \right )}+3600 a^{4} {\mathrm e}^{4 i \left (d x +c \right )}-4000 a^{2} b^{2} {\mathrm e}^{4 i \left (d x +c \right )}+464 b^{4} {\mathrm e}^{4 i \left (d x +c \right )}+150 i a \,b^{3} {\mathrm e}^{6 i \left (d x +c \right )}-375 i a \,b^{3}+2400 a^{4} {\mathrm e}^{2 i \left (d x +c \right )}-3200 a^{2} b^{2} {\mathrm e}^{2 i \left (d x +c \right )}+160 b^{4} {\mathrm e}^{2 i \left (d x +c \right )}-600 i a^{3} b \,{\mathrm e}^{8 i \left (d x +c \right )}+375 i a \,b^{3} {\mathrm e}^{8 i \left (d x +c \right )}+600 a^{4}-1200 a^{2} b^{2}+120 b^{4}\right )}{60 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{5}}+\frac {a^{5} \ln \left (i+{\mathrm e}^{i \left (d x +c \right )}\right )}{d}-\frac {5 a^{3} b^{2} \ln \left (i+{\mathrm e}^{i \left (d x +c \right )}\right )}{d}+\frac {15 a \,b^{4} \ln \left (i+{\mathrm e}^{i \left (d x +c \right )}\right )}{8 d}-\frac {a^{5} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{d}+\frac {5 a^{3} b^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{d}-\frac {15 a \,b^{4} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{8 d}\) | \(510\) |
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Time = 0.26 (sec) , antiderivative size = 196, normalized size of antiderivative = 0.88 \[ \int \sec ^6(c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\frac {15 \, {\left (8 \, a^{5} - 40 \, a^{3} b^{2} + 15 \, a b^{4}\right )} \cos \left (d x + c\right )^{5} \log \left (\sin \left (d x + c\right ) + 1\right ) - 15 \, {\left (8 \, a^{5} - 40 \, a^{3} b^{2} + 15 \, a b^{4}\right )} \cos \left (d x + c\right )^{5} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 48 \, b^{5} + 240 \, {\left (5 \, a^{4} b - 10 \, a^{2} b^{3} + b^{5}\right )} \cos \left (d x + c\right )^{4} + 160 \, {\left (5 \, a^{2} b^{3} - b^{5}\right )} \cos \left (d x + c\right )^{2} + 150 \, {\left (2 \, a b^{4} \cos \left (d x + c\right ) + {\left (8 \, a^{3} b^{2} - 5 \, a b^{4}\right )} \cos \left (d x + c\right )^{3}\right )} \sin \left (d x + c\right )}{240 \, d \cos \left (d x + c\right )^{5}} \]
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Timed out. \[ \int \sec ^6(c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\text {Timed out} \]
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Time = 0.23 (sec) , antiderivative size = 230, normalized size of antiderivative = 1.03 \[ \int \sec ^6(c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\frac {75 \, a b^{4} {\left (\frac {2 \, {\left (5 \, \sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} + 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 600 \, a^{3} b^{2} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} + \log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 120 \, a^{5} {\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + \frac {1200 \, a^{4} b}{\cos \left (d x + c\right )} - \frac {800 \, {\left (3 \, \cos \left (d x + c\right )^{2} - 1\right )} a^{2} b^{3}}{\cos \left (d x + c\right )^{3}} + \frac {16 \, {\left (15 \, \cos \left (d x + c\right )^{4} - 10 \, \cos \left (d x + c\right )^{2} + 3\right )} b^{5}}{\cos \left (d x + c\right )^{5}}}{240 \, d} \]
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Time = 0.56 (sec) , antiderivative size = 410, normalized size of antiderivative = 1.83 \[ \int \sec ^6(c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\frac {15 \, {\left (8 \, a^{5} - 40 \, a^{3} b^{2} + 15 \, a b^{4}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 15 \, {\left (8 \, a^{5} - 40 \, a^{3} b^{2} + 15 \, a b^{4}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) + \frac {2 \, {\left (600 \, a^{3} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 225 \, a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 600 \, a^{4} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{8} - 1200 \, a^{3} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 1050 \, a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 2400 \, a^{4} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} - 2400 \, a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} - 3600 \, a^{4} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 5600 \, a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 640 \, b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 1200 \, a^{3} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 1050 \, a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 2400 \, a^{4} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 4000 \, a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 320 \, b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 600 \, a^{3} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 225 \, a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 600 \, a^{4} b + 800 \, a^{2} b^{3} - 64 \, b^{5}\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{5}}}{120 \, d} \]
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Time = 27.41 (sec) , antiderivative size = 345, normalized size of antiderivative = 1.54 \[ \int \sec ^6(c+d x) (a \cos (c+d x)+b \sin (c+d x))^5 \, dx=\frac {\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )\,\left (2\,a^5-10\,a^3\,b^2+\frac {15\,a\,b^4}{4}\right )}{d}-\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9\,\left (\frac {15\,a\,b^4}{4}-10\,a^3\,b^2\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (\frac {35\,a\,b^4}{2}-20\,a^3\,b^2\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7\,\left (\frac {35\,a\,b^4}{2}-20\,a^3\,b^2\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\left (40\,a^4\,b-40\,a^2\,b^3\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (40\,a^4\,b-\frac {200\,a^2\,b^3}{3}+\frac {16\,b^5}{3}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (60\,a^4\,b-\frac {280\,a^2\,b^3}{3}+\frac {32\,b^5}{3}\right )+10\,a^4\,b+\frac {16\,b^5}{15}-\frac {40\,a^2\,b^3}{3}-\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (\frac {15\,a\,b^4}{4}-10\,a^3\,b^2\right )+10\,a^4\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}-5\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+10\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6-10\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+5\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2-1\right )} \]
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